+0  
 
+1
138
3
avatar+32 

The bases on a baseball field are 60 feet apart. The pitcher's mound is between second base and home plate, 46 feet from home plate. What is the distance from the pitcher's mound to second base? (Assume the field is a square. Round your answer to two decimal places.

 Jul 5, 2021
 #1
avatar+35059 
+1

From 1st base to 2nd base is a 60 ft leg of a right triangle

   the hypotenuse would be from 2nd base to home plate

 

      use pythagorean theorem      d^2 = 60^2 + 60 ^2      d = from second to home = 84.85 ft     You can finish, Yah?

 Jul 5, 2021
 #2
avatar+32 
+1

Using the pythagorean theorem:

a^2 + b^2 = C^2

 

60^2 + 60^2 = (distance to 2nd base)^2

3600 +3600 = (distance to 2nd)^2          

7200 =  (distance to 2nd)^2        

Distance to 2nd = √7200 = 60√2 ≈ 84.85 ft.   distance between home plate and second base   

 

From the above question, it states the distance from home plate to second base is 46ft. Therefore, to calculate the distance from the pitcher's mound to second base we will subtract.

 

84.85 ft - 46 ft =   subtract distance from home plate

38.85 ft               distance from the pitcher's mound to second base

mamabear81  Jul 5, 2021
 #3
avatar+35059 
+1

Yeppers.....That's it !    cheeky

ElectricPavlov  Jul 5, 2021

25 Online Users

avatar