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The perimeter of a rectangle is $40,$ and the length of one of its diagonals is $10 \sqrt{2}.$ Find the area of the rectangle.

 May 23, 2024
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Let's let the two sides of the rectange x and y. 

 

We can use the problem to write the equation

 

2x+2y=40x+y=20

 

Isolating y, we have y=20x

 

Subsituting this value for y into the second part of the qeustion and using the pythaogrean theorem, we have

x2+y2=(102)2x2+(20x)2=200x2+x240x+400=2002x240x+200=0x220x+100=0

 

Finally, we find that we have x = 10. From the first equation, we find that y = 10 as well. 

 

The area is just 10*10=100!

 

Thanks! :)

 May 23, 2024

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