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Let P_1 P_2 P_3 \dotsb P_{10} be a regular polygon inscribed in a circle with radius $1.$ Compute
P_1 P_2 + P_2 P_3 + P_3 P_4 + \dots + P_9 P_{10} + P_{10} P_1

 Aug 15, 2024
 #1
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mmm...take a look at the points given. 

P1P2+P2P3+P3P4++P9P10+P10P1

 

This is essentially just the perimeter of the decagon P1P2P3P4P5...P10

 

The lenngth of one side is essentially

radius/2(1+5)

 

Now that we know one side, we can find the perimeter through the equation

10(1/2)(1+5)=5(1+5)6.18

 

Thus, the answer is 6.18, 

 

Thanks! :)

 Aug 15, 2024
edited by NotThatSmart  Aug 15, 2024

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