Let P_1 P_2 P_3 \dotsb P_{10} be a regular polygon inscribed in a circle with radius $1.$ Compute
P_1 P_2 + P_2 P_3 + P_3 P_4 + \dots + P_9 P_{10} + P_{10} P_1
mmm...take a look at the points given.
P1P2+P2P3+P3P4+⋯+P9P10+P10P1
This is essentially just the perimeter of the decagon P1P2P3P4P5...P10
The lenngth of one side is essentially
radius/2(−1+√5)
Now that we know one side, we can find the perimeter through the equation
10(1/2)(−1+√5)=5(−1+√5)≈6.18
Thus, the answer is 6.18,
Thanks! :)