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The longer leg of a right triangle is 8 more than the shorter leg. The hypotenuse is 6 more than the longer leg. Find all three sides.

 Oct 26, 2021
 #1
avatar+150 
+1

Let's say smaller leg is X

The longer leg is x+8

Hypo is x+14 

a^2 + b^2 = c

so x^2 + (x+8)^2 = (x+14)^2. 
Expand
x^2 + x^2 + 16x + 64 = x^2 + 28x + 196.
Minus x^2 from both sides

x^2 + 16x + 64 = 28x+196
Minus 16x 

x^2 + 64 = 12x + 196
Minus 64

x^2 = 12x + 132.
or
x^2-12x-132 = 0.

From there, hopefully you can solve 

 Oct 26, 2021
 #2
avatar+1608 
0

Good job!!! smiley

civonamzuk  Oct 27, 2021

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