The longer leg of a right triangle is 8 more than the shorter leg. The hypotenuse is 6 more than the longer leg. Find all three sides.
+150 Let's say smaller leg is X
The longer leg is x+8
Hypo is x+14
a^2 + b^2 = c
so x^2 + (x+8)^2 = (x+14)^2.
Expand
x^2 + x^2 + 16x + 64 = x^2 + 28x + 196.
Minus x^2 from both sides
x^2 + 16x + 64 = 28x+196
Minus 16x
x^2 + 64 = 12x + 196
Minus 64
x^2 = 12x + 132.
or
x^2-12x-132 = 0.
From there, hopefully you can solve
