+1557 In triangle ABC, angle A = p + 2q degrees, angle B = 6p - 5q degrees, and angle C = 14p + 8q degrees. Find p (in degrees) in terms of q.
+9 In a triangle, the sum of the angles is always 180 degrees. So, we can set up the following equation:
A+B+C=180
Substituting the given expressions for A, B, and C, we get:
(p+2q)+(6p−5q)+(14p+8q)=180
Simplifying, we get:
21p+5q=180
Solving for p, we find:
p=(180−5q)/21
So, p in terms of q is (180−5q)/21 degrees.
