The cube below has sides of length 4 feet. If a cylindrical section of radius 2 feet is removed from the solid, what is the total remaining volume of the cube? Express your answer in cubic feet in terms of pi
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+981 Hey Guest!
\(\text{volume of the cube} - \text{volume of the cylindrical section} = \text{volume of the remaining solid.} \)
The volume of the cube: \(\text{length} * \text{width} * \text{height} = 4^3 = 64\)
Volume of the cylinder: \(π * \text{radius}^2 * \text{height} = 22π * 4 = 16π\)
\(64-16π=13.73251754\cdots\)
I hope this helped,
Gavin.
