+1206 In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.
+963 To solve this problem, let's note something really important first.
Since in the problem, we have \( AD = AB \), then we can conclude that \(\angle ABD = \angle ADB\)
Thus, we can easily solve the problem from here. We can write the equation
\( ABD = (180 - 17) / 2 = 81.5° \)
Thus, our answer is 81.5
Thanks! :)
