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In triangle ABC, the angle bisector of angle BAC meets BC at D, such that AD = AB. Line segment AD is extended to E, such that angle DBE = angle BAD = 17 degrees. Find angle ABD.

 Jul 1, 2024
 #1
avatar+1252 
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To solve this problem, let's note something really important first. 

 

Since in the problem, we have \( AD = AB \), then we can conclude that \(\angle ABD = \angle ADB\)

 

Thus, we can easily solve the problem from here. We can write the equation

\( ABD = (180 - 17) / 2 = 81.5° \)

 

Thus, our answer is 81.5

 

Thanks! :)

 Jul 1, 2024

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