In triangle $ABC,$ $AB = 15,$ $BC = 9,$ and $AC = 10.$ Find the length of the shortest altitude in this triangle.
Shortest altitude is drawn to the longest side
Area = sqrt [ 17 * (17 - 15) *(17 -10) * (17 - 9) ] = sqrt [17 * 2 * 7 * 8] = 4sqrt (119)
4sqrt (119) = (1/2) 15 * shortest altitude
(8/15)sqrt (119) = shortest altitude ≈ 5.82
+1385 
