+0 In triangle $PQR,$ let $X$ be the intersection of the angle bisector of $\angle P$ with side $\overline{QR}$, and let $Y$ be the foot of the perpendicular from $X$ to side $\overline{PR}$. If $PQ = 8,$ $QR = 5,$ and $PR = 1,$ then compute the length of $\overline{XY}$.
+297 In triangle PQR, let X be the intersection of the angle bisector of \(\angle P\) with side \(\overline{QR}\), and let Y be the foot of the perpendicular from X to side \(\overline{PR}\). If PQ = 8, QR = 5, and PR = 1, then compute the length of \(\overline{XY}\).
Ookie Dookie
No answer. Simply logic
Let me repeat the question, and you try to figure out whats wrong.
PQ = 8, QR = 5, PR = 1.
2 sides of a triangle has to add up to more than the third side, but
\(5+1<8\)
so this triangle is not even possible in the first place.
+297 In triangle PQR, let X be the intersection of the angle bisector of \(\angle P\) with side \(\overline{QR}\), and let Y be the foot of the perpendicular from X to side \(\overline{PR}\). If PQ = 8, QR = 5, and PR = 1, then compute the length of \(\overline{XY}\).
Ookie Dookie
No answer. Simply logic
Let me repeat the question, and you try to figure out whats wrong.
PQ = 8, QR = 5, PR = 1.
2 sides of a triangle has to add up to more than the third side, but
\(5+1<8\)
so this triangle is not even possible in the first place.
