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# Geometry

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Hello :) So this problem I'm having trouble with, I have no idea how to solve it! I don't need an answer, just how to do it. But either works :)

The area of a square garden is 50 squared meters. How long is the diagonal?

Dec 2, 2015

#1
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The side of the square  = sqrt(50)m

The diagonal of any sqare =  sqrt(2)  * tthe side length

I'll let you take it from there, saseflower...!!!!   Dec 2, 2015
edited by CPhill  Dec 2, 2015

#1
+13

The side of the square  = sqrt(50)m

The diagonal of any sqare =  sqrt(2)  * tthe side length

I'll let you take it from there, saseflower...!!!!   CPhill Dec 2, 2015
edited by CPhill  Dec 2, 2015
#2
+10

Hello :) So this problem I'm having trouble with, I have no idea how to solve it! I don't need an answer, just how to do it. But either works :)

The area of a square garden is 50 squared meters. How long is the diagonal?

well  the area of a square is length* length = L2

so

$$L^2=50\\ L=\sqrt{50}\;\;metres \\$$

Now draw the square and use the Pythagorean Theorum to find the diagonal.

$$diagonal^2=(\sqrt{50})^2+(\sqrt{50})^2\\ diagonal^2=50+50\\ diagonal^2=100\\ diagonal=10\;metres\\$$

.
Dec 2, 2015
#3
+10

Thank you both for the answers! :)

Dec 2, 2015
#4
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A2+b2=c2

502+502=c2

2500+2500=c2

5000=c2

/5000=c

70.7106781186547524=c

Dec 2, 2015