Let ABC be a triangle, and let its angle bisectors be AD, BE, and CF, which intersect at I. If DI = 3, BD = 4, and BI = 8, then find the area of triangle ABC.
+133 If I'm understanding correctly, the question seems to have no answer.
The incenter is always inside the triangle; DIB must be a triangle. 3+4<8... it doesn't add up.
