In an isosceles △ABC (AC = BC) its incircle touches the side BC at point T. Given AC = 4 and AT = 3. Find the length of AB.
+1622 Isosceles triangle ABC has AC = BC = 4.
Using the rules of tangents, AT is perpendicular to a leg of triangle ABC. AC = 4 and AT = 3, so using the pythagorean theorem we can get length of segment CT.
CT = \(\sqrt{4^2 - 3^2}\) = \(\sqrt{7}\)
Segment BT = BC - TC = \(4 - \sqrt{7}\)
Then we can use the pythagorean theorem to get AB.
AB = \(\sqrt{3^2 + (4 - \sqrt{7})^2}\)
AB = \(2\sqrt{8 - 2\sqrt{7}}\)
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