Two tangents $\overline{PA}$ and $\overline{PB}$ are drawn to a circle, where $P$ lies outside the circle, and $A$ and $B$ lie on the circle. The length of $\overline{AB}$ is $4,$ and the circle has a radius of $5.$ Find the length $AB.$
Maybe its saying AP = 4? That sounds more reasonable
So this is a kite shape, and the kite is concyclic because opposite angles add to 180
Therefore, the area can be represented by √(9−5)(9−5)(9−4)(9−4)
which is 20
The area can also be represented by the 2 diagonals divided by 2,
√41⋅x2=20
x=4041⋅√41
Maybe its saying AP = 4? That sounds more reasonable
So this is a kite shape, and the kite is concyclic because opposite angles add to 180
Therefore, the area can be represented by √(9−5)(9−5)(9−4)(9−4)
which is 20
The area can also be represented by the 2 diagonals divided by 2,
√41⋅x2=20
x=4041⋅√41