A cone is formed by rotating an isosceles right triangle with leg length 10 about one of its legs. Its surface area is pi times what number?
A cone is formed by rotating an isosceles right triangle with leg length 10 about one of its legs. Its surface area is pi times what number?
Hello Guest!
\(A=A_{\circ}+A_M\)
\(A_{\circ}=10^2\cdot \pi\)
\(A_M=\pi\cdot r\cdot s=\pi\cdot 10\cdot 10\sqrt{2}\\ A_M=\pi\cdot 10^2\cdot \sqrt{2}\)
\(\color{black}A=\pi \cdot(10^2+10^2\cdot \sqrt{2})\\ A=\pi\cdot 10^2(1+\sqrt{2})\\ A=\pi \cdot 241.421 \)
The surface area is \(\pi \cdot 241.421\)
!.