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Trapezoid $ABCD$ is inscribed in the semicircle with diameter $\overline{AB}$, as shown below.  Find the radius of the semicircle.  Find the area of ABCD.

 

PQDC is a square.

 

 Jun 24, 2024

Best Answer 

 #1
avatar+85 
+1

to find the radius of the circle imagine a point M as the midpoint of QP. MC would then be the radius of the semicircle. MP is 8 and CP is 16 so we can find the hypotenuse by doing 64+256 then square rooting sqrt320 is \(\boxed{8\sqrt[]{5}}\)

the area of the trapezoid would be (34 +16)/2 * 16 or 25*16 or 100*4 or \(\boxed{400}\) that wasnt so bad... :P

 Jun 24, 2024
 #1
avatar+85 
+1
Best Answer

to find the radius of the circle imagine a point M as the midpoint of QP. MC would then be the radius of the semicircle. MP is 8 and CP is 16 so we can find the hypotenuse by doing 64+256 then square rooting sqrt320 is \(\boxed{8\sqrt[]{5}}\)

the area of the trapezoid would be (34 +16)/2 * 16 or 25*16 or 100*4 or \(\boxed{400}\) that wasnt so bad... :P

shmewy Jun 24, 2024

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