+506 Trapezoid $ABCD$ is inscribed in the semicircle with diameter $\overline{AB}$, as shown below. Find the radius of the semicircle. Find the area of ABCD.
PQDC is a square.
+83 to find the radius of the circle imagine a point M as the midpoint of QP. MC would then be the radius of the semicircle. MP is 8 and CP is 16 so we can find the hypotenuse by doing 64+256 then square rooting sqrt320 is \(\boxed{8\sqrt[]{5}}\)
the area of the trapezoid would be (34 +16)/2 * 16 or 25*16 or 100*4 or \(\boxed{400}\) that wasnt so bad... :P
+83 to find the radius of the circle imagine a point M as the midpoint of QP. MC would then be the radius of the semicircle. MP is 8 and CP is 16 so we can find the hypotenuse by doing 64+256 then square rooting sqrt320 is \(\boxed{8\sqrt[]{5}}\)
the area of the trapezoid would be (34 +16)/2 * 16 or 25*16 or 100*4 or \(\boxed{400}\) that wasnt so bad... :P
