Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 10 feet and a height of 19 feet. Container B has a diameter of 14 feet and a height of 12 feet. Container A is full of water and the water is pumped into Container B until Container A is empty.

After the pumping is complete, what is the volume of water in Container B, to the nearest tenth of a cubic foot?

Guest Apr 16, 2021

#1**+2 **

Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 10 feet and a height of 19 feet. Container B has a diameter of 14 feet and a height of 12 feet. Container A is full of water and the water is pumped into Container B until Container A is empty.

After the pumping is complete, what is the volume of water in Container B, to the nearest tenth of a cubic foot?

**Hi Guest!**

\(\Delta V=\frac{\pi}{4}(10^2\cdot 19-14^2\cdot 12)ft^3=-355ft^3\)

Tray B is larger than Tray A. The pumping process ends when container B is full.

Then is the volume of water in container B \(\frac{\pi}{4}\cdot 14^2\cdot 12\ cft=\color{blue}1847.3\ cft\)

!

asinus Apr 16, 2021

#2**+2 **

Basically, the entire volume of A is now in B when done

volume of A = pi r^2 h = pi (5^2)19 =~ 1492.36 ft^{3} = volume in B when all of A is transferred

( B has volume of 1847 ft^{3} so all of A will fit)

ElectricPavlov Apr 16, 2021