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# Geometry

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Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 10 feet and a height of 19 feet. Container B has a diameter of 14 feet and a height of 12 feet. Container A is full of water and the water is pumped into Container B until Container A is empty.

After the pumping is complete, what is the volume of water in Container B, to the nearest tenth of a cubic foot?

Apr 16, 2021

#1
+11864
+2

Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 10 feet and a height of 19 feet. Container B has a diameter of 14 feet and a height of 12 feet. Container A is full of water and the water is pumped into Container B until Container A is empty.
After the pumping is complete, what is the volume of water in Container B, to the nearest tenth of a cubic foot?

Hi Guest!

$$\Delta V=\frac{\pi}{4}(10^2\cdot 19-14^2\cdot 12)ft^3=-355ft^3$$

Tray B is larger than Tray A. The pumping process ends when container B is full.

Then is the volume of water in container B $$\frac{\pi}{4}\cdot 14^2\cdot 12\ cft=\color{blue}1847.3\ cft$$

!

Apr 16, 2021
#2
+33689
+2

Basically, the entire volume of A is now in B when done

volume of A   = pi r^2 h  =  pi (5^2)19 =~ 1492.36 ft3     = volume in B when all of A is transferred

( B has volume of  1847  ft3     so all of A will fit)

Apr 16, 2021