Let ABCD be a trapezoid with bases BC and AD. In this trapezoid, angle DBA = 105, angle ABD = 43, and angle BCD = \(147\). Find angle CBD, in degrees.
+1622 First of all, if we have a trapezoid with bases BC and AD, then DB would be a diagonal. And DBA is the same angle as ABD, so they can't be different angles. In your problem, it says DBA = 105, and ABD = 43, but they are the same angle and 105 is not equal to 43. I think what you might mean is that the 3 interior angles of the trapezoid are 105, 43, and 147 degrees.
If that is so, then angle CBD is 360 - (105 + 43 + 147) = 165 degrees.
Also that wouldnt be a trapezoid.
