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Find the area of the triangle with side lengths sqrt(70), sqrt(70), and sqrt(28).

 Sep 29, 2020
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*** edited***

Find 'h' of the isosceles triangle

 

(sqrt 70 )^2 =  (1/2sqrt 28)^2 + h^2

h= sqrt 63

 

Area = 1/2 b h   = 1/2  sqrt 28  sqrt 63         you can finish......

 

 

 

You could also do the Heron's Formula calculations to find area (though it is longer) :

 

https://www.mathopenref.com/heronsformula.html

 Sep 29, 2020
edited by ElectricPavlov  Sep 29, 2020
edited by ElectricPavlov  Sep 29, 2020
edited by ElectricPavlov  Sep 29, 2020

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