Find the area of the triangle with side lengths sqrt(70), sqrt(70), and sqrt(28).
+36915 *** edited***
Find 'h' of the isosceles triangle
(sqrt 70 )^2 = (1/2sqrt 28)^2 + h^2
h= sqrt 63
Area = 1/2 b h = 1/2 sqrt 28 sqrt 63 you can finish......
You could also do the Heron's Formula calculations to find area (though it is longer) :
https://www.mathopenref.com/heronsformula.html
