Let triangle ABC be a right triangle such that B is a right angle. A circle with diameter of BC meets side AC at D. If the area of ABC is 180 and AC = 35, then what is BD?

Guest Jan 1, 2021

#1**-2 **

Hint: BD is the altitude of a triangle ABC. You can use the isosceles right triangle for your convenience.

My calculations show that BD = 17.5

If you don't prove me wrong then I guess I'm right.

jugoslav Jan 2, 2021

#3**+2 **

My above answer is incorrect!!! I'll give it a try again.

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Let triangle ABC be a right triangle such that B is a right angle. A circle with a diameter of BC meets side AC at D. If the area of ABC is 180 and AC = 35, then what is BD?

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AC = 35 [ABC] = 180 u^{2}

**BD = (180 * 2) / 35 **

jugoslav
Jan 3, 2021