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Let triangle ABC be a right triangle such that B is a right angle. A circle with diameter of BC meets side AC at D. If the area of ABC is 180 and AC = 35, then what is BD?

 Jan 1, 2021
 #1
avatar+836 
-2

Hint:   BD is the altitude of a triangle ABC. You can use the isosceles right triangle for your convenience.laugh

 

My calculations show that BD = 17.5 cool

 

If you don't prove me wrong then I guess I'm right.laugh

 Jan 2, 2021
 #3
avatar+836 
+2

My above answer is incorrect!!!cheeky cool I'll give it a try again.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Let triangle ABC be a right triangle such that B is a right angle. A circle with a diameter of BC meets side AC at D. If the area of ABC is 180 and AC = 35, then what is BD?

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

AC = 35       [ABC] = 180 u2

 

BD = (180 * 2) / 35 smiley

jugoslav  Jan 3, 2021
edited by jugoslav  Jan 3, 2021
 #2
avatar+31511 
+3

I get the following:

 Jan 2, 2021

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