In the figure, angles $\angle ABC$ and $\angle AST$ are right angles. If $AC = 35,$ then what is $AS$?
So then here is my explanation:
To find the length of segment AS in triangle AST.
You have information about the lengths of AC, AT, and BT.
Using the Pythagorean theorem, you calculate BC as √(AC² - AB²), which is √(35² - 20²) = √825.
Then, you find CT by adding BC and TB:
CT² = BC² + TB²
= 825 + 9²
= 906.
Now, you use the Pythagorean theorem for triangle CST to get CS² + ST² = CT² = 906.
And for triangle AST, you have AS² + ST² = AT², which is 121.
Subtracting equation 1 from equation 2, you get
AS² - CS² = -785.
Rearrange to get :
AS² - (35 - AS)² = -785.
Further simplify to AS² - AS² + 70AS - 35² = -785.
Now, solve for AS, and you get AS ≈ 6.28.
So, the length of segment AS is approximately 6.28 units.
Um, is there an image to this question, becuase I have no idea without any image.
I think there might be some things missing but I heard of the question, and I think it is:
In the figure, angles ABC and AST are right angles. If AC = 35, AT = 11, and BT = 9, then what is AS?
So then here is my explanation:
To find the length of segment AS in triangle AST.
You have information about the lengths of AC, AT, and BT.
Using the Pythagorean theorem, you calculate BC as √(AC² - AB²), which is √(35² - 20²) = √825.
Then, you find CT by adding BC and TB:
CT² = BC² + TB²
= 825 + 9²
= 906.
Now, you use the Pythagorean theorem for triangle CST to get CS² + ST² = CT² = 906.
And for triangle AST, you have AS² + ST² = AT², which is 121.
Subtracting equation 1 from equation 2, you get
AS² - CS² = -785.
Rearrange to get :
AS² - (35 - AS)² = -785.
Further simplify to AS² - AS² + 70AS - 35² = -785.
Now, solve for AS, and you get AS ≈ 6.28.
So, the length of segment AS is approximately 6.28 units.