Two sectors of a circle of radius 12 overlap as shown, with P and R as the centers of the respective circles. Determine the area of the shaded region.
Let the intersection point directly above \(P\) as \(A\), and let the point that is to the left of \(P\) be \(B\)
The area of \(\triangle ABP = 12 \times 12 \div 2 = 72\)
The area of the circular region \(ABP\) is \( {1 \over 4} \times 12^2 \times \pi = 36 \pi \)
Now, note that the area of the shaded region is \(2 (\text{circular region of ABP} - \triangle ABP) \)
Substituting what we know, we find that the area of the shaded region is \(\color{brown}\boxed{72 \pi - 144}\)
Let the intersection point directly above \(P\) as \(A\), and let the point that is to the left of \(P\) be \(B\)
The area of \(\triangle ABP = 12 \times 12 \div 2 = 72\)
The area of the circular region \(ABP\) is \( {1 \over 4} \times 12^2 \times \pi = 36 \pi \)
Now, note that the area of the shaded region is \(2 (\text{circular region of ABP} - \triangle ABP) \)
Substituting what we know, we find that the area of the shaded region is \(\color{brown}\boxed{72 \pi - 144}\)