Geometry

See diagram below

Angle YBP  = 180  - 65 - 60  = 55°

Angle BYP  =  180  - 75 - 60 = 45°

So

Angle BYP  =  180  - 55 - 45  = 80°

And Angle CYX is a vertical  angle to BYP  ....so it = 80°

So.... CXY  =  180  - 60  - 80   =   40°

Glad it helped , Tertre......waiting to see what the answer is to your red/white ball question to see if I got it correct!

Let's see if I can solve this:

Since $\triangle ABC$ and $\triangle PQR$ are equilateral, then $\angle ABC=\angle ACB=\angle RPQ=60^\circ$.

Therefore, $\angle YBP = 180^\circ-65^\circ-60^\circ=55^\circ$  and $\angle YPB = 180^\circ-75^\circ-60^\circ=45^\circ$ .

In $\triangle BYP$, we have $\angle BYP = 180^\circ - \angle YBP - \angle YPB = 180^\circ - 55^\circ-45^\circ=80^\circ$.

Since $\angle XYC = \angle BYP$ , then $\angle XYC=80^\circ$.

In $\triangle CXY$, we have $\angle CXY = 180^\circ - 60^\circ - 80^\circ = 40^\circ$.

So our final answer is $\boxed{40}$ degrees.