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In a right triangle, the longer leg and the hypotenuse have consecutive integer lengths whose sum is 121 inches. In inches, what is the perimeter of the triangle?

 Jul 26, 2021
 #1
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Wait isnt the longer leg the hypotenuse?

 Jul 26, 2021
 #2
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Also to solve it just remeber the pythagorean theorem, a^2+b^2=c^2 to solve this. FYI c is the hypotenuse

Tr1ck3d  Jul 26, 2021
 #3
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Longer leg = x 

Hypotenuse = x + 1

x + (x + 1) = 121

x = 60     

Shorter leg = sqrt[(x + 1)2 - x2] = 11

perimeter = 11 + 60 + 61

 Jul 26, 2021

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