In a right triangle, the longer leg and the hypotenuse have consecutive integer lengths whose sum is 121 inches. In inches, what is the perimeter of the triangle?

Wait isnt the longer leg the hypotenuse?

Also to solve it just remeber the pythagorean theorem, a^2+b^2=c^2 to solve this. FYI c is the hypotenuse

Longer leg = x

Hypotenuse = x + 1

x + (x + 1) = 121

x = 60

Shorter leg = sqrt[(x + 1)^{2} - x^{2}] = 11

perimeter = 11 + 60 + 61