+0  
 
0
240
1
avatar

Let ABC be a right triangle such that B is a right angle. A circle with diameter of BC meets side AC at D. If the area of ABC is 150 and AC = 40 then what is BD?

 Apr 23, 2022

Best Answer 

 #1
avatar+14913 
+2

 what is BD?

 

Hello Guest!

 

BD is perpendicular to AC, so it is the height of triangle ABC. So is

\(BD=\frac{2\cdot 150}{40}=\color{blue}7.5\)

laugh  !

 Apr 23, 2022
 #1
avatar+14913 
+2
Best Answer

 what is BD?

 

Hello Guest!

 

BD is perpendicular to AC, so it is the height of triangle ABC. So is

\(BD=\frac{2\cdot 150}{40}=\color{blue}7.5\)

laugh  !

asinus Apr 23, 2022

3 Online Users

avatar