+566 As shown in the diagram, NM is the median of trapezoid ABCD and PQ is the median of trapezoid ABMN. We know AB = 5 and DC = 17. Find PQ.
+591 If NM is the median of trapezoid ABCD, then that means NM is the average of the two heights, which in this case are 5 and 17. so that means NM= $\frac{5+17}2=11$
now to find the median of trapezoid ABMN, we have to do the same thing, take the average of the two heights, which in this case are 5 and 11. This means that PQ=$\frac{5+11}2=\boxed{8}$
+591 If NM is the median of trapezoid ABCD, then that means NM is the average of the two heights, which in this case are 5 and 17. so that means NM= $\frac{5+17}2=11$
now to find the median of trapezoid ABMN, we have to do the same thing, take the average of the two heights, which in this case are 5 and 11. This means that PQ=$\frac{5+11}2=\boxed{8}$
