The number of diagonals in a certain regular polygon is equal to five times the number of sides. How many sides does this polygon have?

Maplesnowy Jun 19, 2018

#1**0 **

Solve for n:

5 n = 1/2 n (n - 3)

Write the quadratic polynomial on the right-hand side in standard form.

Expand out terms of the right-hand side:

5 n = n^2/2 - (3 n)/2

Move everything to the left-hand side.

Subtract n^2/2 - (3 n)/2 from both sides:

(13 n)/2 - n^2/2 = 0

Factor the left-hand side.

Factor n and constant terms from the left-hand side:

-1/2 n (n - 13) = 0

Multiply both sides by a constant to simplify the equation.

Multiply both sides by -2:

n (n - 13) = 0

Find the roots of each term in the product separately.

Split into two equations:

n - 13 = 0 or n = 0

Look at the first equation: Solve for n.

Add 13 to both sides:

**n = 13** or n = 0(Discard) . **So this is a 13-gon polygon with 65 diagonals.**

Guest Jun 19, 2018