In triangle ABC, the angle bisector of angle BAC meets AC at D. If angle BAC = 60, angle ABC = 60, and AD = 24, then find the area of triangle ABC.
+2668 Note that \(\triangle ABC \) is equilateral, so angle bisector \(AD\) is also an altitude of a 30-60-90 triangle.
This means that the hypotenuse is \(24 \times {2 \sqrt3 \over 3} = 16 \sqrt 3\)
So the area of the triangle is \((16 \sqrt 3)^2 \times {\sqrt3 \over 4} = \color{brown}\boxed{192 \sqrt 3}\)
