A rectangular prism has a length of $3$, a width of $5$, and a height of $11$. What is the distance between two opposite corners of the prism?
To find the distance between two opposite corners of the rectangular prism, we can visualize a diagonal line going through the entire prism. This diagonal will form a right triangle with sides that correspond to the lengths, width, and height of the prism.
We can use the Pythagorean Theorem to find the length of this diagonal.
Pythagorean Theorem:
a^2 + b^2 = c^2
where:
a and b are the lengths of the two legs of a right triangle.
c is the length of the hypotenuse (the diagonal in this case).
Applying the theorem:
In our case:
a = length of the prism = 3 units
b = width of the prism = 5 units
c = diagonal length (what we want to find)
Solve for c (diagonal length):
c^2 = a^2 + b^2
c^2 = 3^2 + 5^2
c^2 = 9 + 25
c^2 = 34
Taking the square root of both sides (remembering there might be positive and negative square roots), we get:
c = ±√34
Since c represents a distance (and cannot be negative), we take the positive square root:
c = √34 units
Therefore, the distance between two opposite corners of the rectangular prism is √34 units. (This is the exact answer, but you can approximate it to a decimal value if needed.)