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A boat in calm seas travels in a straight line and ends the trip 22 km west and 53 km north of its original position. To the nearest tenth of a degree, find the direction of the trip.

 Feb 12, 2020
 #1
avatar+22108 
+1

arctan (53/(-22) )   =   112.5 degrees

 Feb 12, 2020
edited by Guest  Feb 12, 2020
 #3
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I have to show my work.

Guest Feb 12, 2020
 #4
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I did show the work......

    tangent = opp/adjacent

                 = 53 / -22

 

arctan 53 / -22 =   112.5 degrees   (it is in the second quadrant     y is positive (53)   x is negative (22)

Guest Feb 12, 2020
 #5
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Okay, now what do I say for the direction...My teacher will count off If I don't answer the whole question

Guest Feb 12, 2020
 #6
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ummmm can't you just do it yourself?

 

its like 5 seconds....

CalculatorUser  Feb 12, 2020
 #2
avatar+2850 
+1

SOH CAH TOA

 

We use TOA in this case because only the legs of a triangle is used. We are also calculating the angle of elevation.

 

Opposite = 53

 

Adjacent = 22

 

Tan(x) = 53/22

 

x = arctan(53/22)

 

Is this correct?

 

 

TBH web2.0calc should implement a drawing program where you can draw something quickly and insert it.

 Feb 12, 2020
edited by CalculatorUser  Feb 12, 2020

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