A boat in calm seas travels in a straight line and ends the trip 22 km west and 53 km north of its original position. To the nearest tenth of a degree, find the direction of the trip.

Guest Feb 12, 2020

#1

#4**0 **

I did show the work......

tangent = opp/adjacent

= 53 / -22

arctan 53 / -22 = 112.5 degrees (it is in the second quadrant y is positive (53) x is negative (22)

Guest Feb 12, 2020

#2**+1 **

SOH CAH TOA

We use TOA in this case because only the legs of a triangle is used. We are also calculating the angle of elevation.

Opposite = 53

Adjacent = 22

Tan(x) = 53/22

x = arctan(53/22)

Is this correct?

TBH web2.0calc should implement a drawing program where you can draw something quickly and insert it.

CalculatorUser Feb 12, 2020