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The giant earthmover used for open-air coal mining has rubber circular tires 11.5 feet in diameter. How many revolutions does each tire make during a six-mile trip? Express your answer to the nearest whole number.

codehtml127  Jun 29, 2018
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In each revoution, the tire travels  pi * diameter =  11.5 pi  ft      (1)

 

6 mlies  = 6 * 5280  ft   (2)

 

So....the number of revolutions that the tire makes is   (2)  / (1) =

 

[ 6 * 5280 ]   /[  11.5 * pi  ] ≈  877 revolutions

 

cool cool cool

CPhill  Jun 29, 2018

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