+0  
 
0
55
1
avatar

Point Y is on a circle and point P lies outside the circle such that PY is tangent to the circle. Point A is on the circle such that segment PA meets the circle again at point B. If PA = 15 and PY = \(11\), then what is AB?

 

 Feb 15, 2022
 #1
avatar+122390 
+1

We have this relationship  (secant - tangent theorem )

 

PY^2  = AP * PB

 

11^2  =  15 * PB

 

121 / 15  = PB  

 

So

 

AB = AP - PB

 

AB  = 15 - 121 / 15  =   (225 -121) / 15   =   104 / 15

 

cool cool cool

 Feb 15, 2022

17 Online Users

avatar