+1365 There's a pretty handy formula to find the circumradius of a triangle.
We have \(\frac{(abc)}{\sqrt{(a + b + c)(b + c - a)(c + a - b)(a + b - c)}}\) where a, b, and c are the sidelegnths.
Here, we just have \(\frac{a^3}{\sqrt{3a^4}} = \frac{a^3}{a^2 \cdot \sqrt3}= \frac{a}{\sqrt{3}}\).
So \(\frac{a}{\sqrt3}\) is our answer.
Thank You! :)
This was the post that got me to 300 points LOL :)
+1365 There's a pretty handy formula to find the circumradius of a triangle.
We have \(\frac{(abc)}{\sqrt{(a + b + c)(b + c - a)(c + a - b)(a + b - c)}}\) where a, b, and c are the sidelegnths.
Here, we just have \(\frac{a^3}{\sqrt{3a^4}} = \frac{a^3}{a^2 \cdot \sqrt3}= \frac{a}{\sqrt{3}}\).
So \(\frac{a}{\sqrt3}\) is our answer.
Thank You! :)
This was the post that got me to 300 points LOL :)
