Let AB and CD be chords of a circle, that meet at point Q inside the circle. If AQ = 6, BQ = 14, and CD = 38, then find the minimum length of CQ.
Intersecting Chord Theorem
AQ * QB = CQ * QD
6 * 14 = x * ( 38 - x)
84 = 38x - x^2
x^2 -38x + 84 = 0
x = ( 38 - sqrt [ 38^2 - 4* 84 ] ) / 2 ≈ 2.356 = min for CQ
