yeah it seems to be glitched -- but i somehow managed to see the image by clicking around LOL
the exterior angles of a polygon ALWAYS add up to $ 180^\circ $
since we know that, we can write the sum of all that we are given and write it all equal to $ 180^\circ $
$ \large[ (5x+4)+(4x+9)+(9x-6)+(4x+1)+(7x+4)=180 \large]^\circ $
$(5x+4+4x+9+9x-6+4x+1+7x+4=180)^\circ $
$ ( 29x+12=180)^\circ $
$ ( 29x=168)^\circ $
$ \boxed{ (x=\frac{168}{29}})^\circ $ which we can say just about $ \boxed{5.8^\circ} $
yeah it seems to be glitched -- but i somehow managed to see the image by clicking around LOL
the exterior angles of a polygon ALWAYS add up to $ 180^\circ $
since we know that, we can write the sum of all that we are given and write it all equal to $ 180^\circ $
$ \large[ (5x+4)+(4x+9)+(9x-6)+(4x+1)+(7x+4)=180 \large]^\circ $
$(5x+4+4x+9+9x-6+4x+1+7x+4=180)^\circ $
$ ( 29x+12=180)^\circ $
$ ( 29x=168)^\circ $
$ \boxed{ (x=\frac{168}{29}})^\circ $ which we can say just about $ \boxed{5.8^\circ} $
I think you're right.
Using the same solution idea as UsernameTooShort.
29x + 12 = 360
x = 12
=^._.^=
oh lord i never noticed -- yes they indeed do add up to 360
at that moment i was working with triangles so thats why i was thinking of 180 LOL