ABC is a right triangle with angle C=90 degrees. AC = 10 and BC = 24. Point P is located inside ABC such that the distance from P to AB is twice the distance from P to AC, and the distance from P to AC is equal to the distance from P to BC. In units, what is the distance from P to AB?
+1641 ABC is a right triangle with an angle of C=90 degrees. AC = 10 and BC = 24. Point P is located inside ABC such that the distance from P to AB is twice the distance from P to AC, and the distance from P to AC is equal to the distance from P to BC. In units, what is the distance from P to AB?
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[ABC] = 120
x2 + 1/2[x(10-x) + x(24-x)] + 26x = 120
x = 120 / 43
The distance from P to AB = 2x
