ABC is a right triangle with angle C=90 degrees. AC = 10 and BC = 24. Point P is located inside ABC such that the distance from P to AB is twice the distance from P to AC, and the distance from P to AC is equal to the distance from P to BC. In units, what is the distance from P to AB?

Guest Jul 13, 2021

#1**+2 **

ABC is a right triangle with an angle of C=90 degrees. AC = 10 and BC = 24. Point P is located inside ABC such that the distance from P to AB is twice the distance from P to AC, and the distance from P to AC is equal to the distance from P to BC. In units, what is the distance from P to AB?

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[ABC] = 120

x^{2} + 1/2[x(10-x) + x(24-x)] + 26x = 120

x = 120 / 43

**The distance from P to AB = 2x**

jugoslav Jul 14, 2021