+216 We have a triangle $\triangle ABC$ and a point $K$ on $BC$ such that $AK$ is an altitude to $\triangle ABC$. If $AC = 8,$ $BK = 2$, and $CK = 3,$ then what is $AB$?
+1950 We knowt hat AK is the altitude, so we have
AK=√AC2−CK2=√82−32=√55 from the pythagorean theorem.
We can now find AB, with
AB=√AK2+BK2=√55+4=√59
so AB is √59
Thanks! :)
