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# geometry

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a spherical paintball measures 1.5 in diameter how much paint is in it?

Guest May 18, 2017

#1
+227
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So what you'd want to do is find the volume of the sphere, since you're finding out how much paint it can hold. The volume can be found using the equation:

$$V = \frac{4}{3} \pi r^3$$

So, we're given the diameter. Since d = 2r, we can make that r = (1/2)d to find the radius, which would give us 0.75.

Plugging that into our volume equation gives:

$$V = \frac{4}{3} \pi (\frac{3}{4})^3$$

We can simplify that down to:

$$V = \frac{9}{16} \pi$$

So the paintball holds (9/16)pi units^3 of paint.

ThisGuy  May 18, 2017
#1
+227
+3

So what you'd want to do is find the volume of the sphere, since you're finding out how much paint it can hold. The volume can be found using the equation:

$$V = \frac{4}{3} \pi r^3$$

So, we're given the diameter. Since d = 2r, we can make that r = (1/2)d to find the radius, which would give us 0.75.

Plugging that into our volume equation gives:

$$V = \frac{4}{3} \pi (\frac{3}{4})^3$$

We can simplify that down to:

$$V = \frac{9}{16} \pi$$

So the paintball holds (9/16)pi units^3 of paint.

ThisGuy  May 18, 2017