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A, B, and C are three points on a plane such that AB=BC=1 and CA= sqrt 3. Draw three circles whose diameters are AB},BC, and CA, respectively. The area of the region included in all three circles (the grey region below) is \(\dfrac a b \pi +\dfrac {\sqrt c} d\) in simplest form, so a, b, c, d are positive integers, a and b are relatively prime, and c is not divisible by the square of a prime. Enter the values of a,b,c,d in order, separating by commas.

 Feb 3, 2021
 #1
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The area is 3/4*pi + sqrt(3)/2, so the answer is "3,4,3,2".

 Feb 3, 2021

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