+594 Given f(x)=3x2+5 and g(x)=x−2 .
What is (fg)(x) ?
A. 3x3−10
B. −3x2+x−7
C. 3x3−6x2+5x−10
D. 3x2−x+7
Given f(x)=2x2−5x−3 and g(x)=2x2+x .
What is (fg)(x) ?
+36916 First one:
(3X^2 +5)(x-2) = 3x^3 - 6x^2 +5x - 10
Second one is written incorrectly, I think you meant f/g(x)
f(x) = 2x^2-5x-3 = (2x+1)(x-3)
then f/g = (2x+1)(x-3) / (x)(2x +1) x cannot equal 0 or -1/2 because the denominator would be ZERO
Simplify to (x-3)/x (the (2x+1)'s 'cancel out')
+36916 First one:
(3X^2 +5)(x-2) = 3x^3 - 6x^2 +5x - 10
Second one is written incorrectly, I think you meant f/g(x)
f(x) = 2x^2-5x-3 = (2x+1)(x-3)
then f/g = (2x+1)(x-3) / (x)(2x +1) x cannot equal 0 or -1/2 because the denominator would be ZERO
Simplify to (x-3)/x (the (2x+1)'s 'cancel out')
