+0

# Given that $a$ and $b$ are real numbers such that $-3\leq a\leq1$ and $-2\leq b\leq 4$, and values for $a$ and $b$ are chosen at random,

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Given that $a$ and $b$ are real numbers such that $-3\leq a\leq1$ and $-2\leq b\leq 4$, and values for $a$ and $b$ are chosen at random, what is the probability that the product $a\cdot b$ is positive? Express your answer as a common fraction.

Aug 1, 2021

#1
+34316
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(not positive of this)

TO be positive   both a and b  must be negative   OR   both  a and b must be positive

a neg  * b neg

3/4      *  2/6    =    3/12            because 3/4 of the a range is negative and 2/6 of the range of b is negative

a pos  *  b pos

1/4     *   2/6     = 2/12

3/12    +   2/12   = 5/12

Aug 1, 2021
#2
0

yes that is correct tysm!!!

Guest Aug 1, 2021
#3
+34316
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Yay   ....thanx for the feedback...it is nice to know sometimes, when doubtful of my answers, that the answer was correct !

ElectricPavlov  Aug 1, 2021