Given that k is a positive integer less than 6, how many values can k take on such that \($3x \equiv k \pmod{6}$\) has no solutions in x?
If x= 0 what is k
if x=1 what is k
If x=2 what is k
if x=3 what is k
If x= 4 what is k
if x=5 what is k
If x= 6 what is k
if x=7 what is k
If x= 8 what is k
if x=9 what is k
etc
What have you found
Which values is it posible for k to take
Can you finish it now ?
+64 
