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Given that \(f(x) = x^k\) where \(k > 0\), what is the range of \(f(x)\) on the interval \([1, 0)\)?

 Mar 8, 2019
 #1
avatar+17990 
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Hmmmm....I think the greatest value will be  '1'       1^k   will always be 1 when k>0      as you approach 0 the value will get mucho smaller for larger values of k  ...approaching 0 

so range would look something like    (0,1]                  (I think! cheeky)

 Mar 8, 2019

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