+0  
 
+1
1042
1
avatar+473 

Given that x is a multiple of 23478, what is the greatest common divisor of \(f(x)=(2x+3)(7x+2)(13x+7)(x+13)\)  and x?

 Feb 2, 2018

Best Answer 

 #1
avatar
+2

Since 23478 prime factors are = 2 * 3 * 7 * 13 * 43, and the first 4 factors are common to the polynomial f(x)=(2x+3)(7x+2)(13x+7)(x+13), therefore no matter what value x takes, the GCD of the polynomial and x will ALWAYS be = 2 x 3 x 7 x 13 = 546 !!.

 Feb 2, 2018
 #1
avatar
+2
Best Answer

Since 23478 prime factors are = 2 * 3 * 7 * 13 * 43, and the first 4 factors are common to the polynomial f(x)=(2x+3)(7x+2)(13x+7)(x+13), therefore no matter what value x takes, the GCD of the polynomial and x will ALWAYS be = 2 x 3 x 7 x 13 = 546 !!.

Guest Feb 2, 2018

14 Online Users

avatar