+26367 Given the geometric sequence: 9, 3, 1, ... . Find S6
ratio r = $$\small{\text{$
\frac{3}{9}=\frac{1}{3} $}}$$ and $$\small{\text{$a=9$}}$$ so
$$\small{\text{$
\boxed{a_n=a\cdot
\left(
\frac{1}{3}\right)^{n-1}}
$}}$$
$$s_6=9+3+1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\\ \\
s_6=13+0.\overline{481}\\\\
s_6=13.\overline{481}$$
+26367 Given the geometric sequence: 9, 3, 1, ... . Find S6
ratio r = $$\small{\text{$
\frac{3}{9}=\frac{1}{3} $}}$$ and $$\small{\text{$a=9$}}$$ so
$$\small{\text{$
\boxed{a_n=a\cdot
\left(
\frac{1}{3}\right)^{n-1}}
$}}$$
$$s_6=9+3+1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\\ \\
s_6=13+0.\overline{481}\\\\
s_6=13.\overline{481}$$
