Given z_{1} = -3 + 3i and z_{2} = 6cos150° + 6isin150°, can you help me to explain why z_{1} = z_{2 ?}

Guest Mar 2, 2019

#1**+3 **

Is that supposed to be __150 ?__

__I think __

__Given __

-3 +3i it should be 4.24 cos 135 + i 4.24 sin 135 DO you have some numbers incorrect?

Oh now I see....your question header and your question text are different

Given -3 sqrt(3) + 3 i |z| = r =sqrt [ (-3sqrt3)^2 + 3^2 ] = 6

then 6 cos 150 = -3 sqrt3 and 6i sin 150 = 3i SO the points are the same on the graph.....

ElectricPavlov Mar 2, 2019

edited by
ElectricPavlov
Mar 2, 2019

edited by ElectricPavlov Mar 2, 2019

edited by ElectricPavlov Mar 2, 2019

edited by ElectricPavlov Mar 2, 2019

edited by ElectricPavlov Mar 2, 2019

#1**+3 **

Best Answer

Is that supposed to be __150 ?__

__I think __

__Given __

-3 +3i it should be 4.24 cos 135 + i 4.24 sin 135 DO you have some numbers incorrect?

Oh now I see....your question header and your question text are different

Given -3 sqrt(3) + 3 i |z| = r =sqrt [ (-3sqrt3)^2 + 3^2 ] = 6

then 6 cos 150 = -3 sqrt3 and 6i sin 150 = 3i SO the points are the same on the graph.....

ElectricPavlov Mar 2, 2019

edited by
ElectricPavlov
Mar 2, 2019

edited by ElectricPavlov Mar 2, 2019

edited by ElectricPavlov Mar 2, 2019

edited by ElectricPavlov Mar 2, 2019

edited by ElectricPavlov Mar 2, 2019