Given z1 = -3 
+ 3i and z2 = 6cos150° + 6isin150°, can you help me to explain why z1 = z2 ?
+37146 Is that supposed to be 150 ?
I think
Given
-3 +3i it should be 4.24 cos 135 + i 4.24 sin 135 DO you have some numbers incorrect?
Oh now I see....your question header and your question text are different
Given -3 sqrt(3) + 3 i |z| = r =sqrt [ (-3sqrt3)^2 + 3^2 ] = 6
then 6 cos 150 = -3 sqrt3 and 6i sin 150 = 3i SO the points are the same on the graph.....
+37146 Is that supposed to be 150 ?
I think
Given
-3 +3i it should be 4.24 cos 135 + i 4.24 sin 135 DO you have some numbers incorrect?
Oh now I see....your question header and your question text are different
Given -3 sqrt(3) + 3 i |z| = r =sqrt [ (-3sqrt3)^2 + 3^2 ] = 6
then 6 cos 150 = -3 sqrt3 and 6i sin 150 = 3i SO the points are the same on the graph.....
