√36x^2

3√ (128x^7) = 3√( 64*2*x^7) = 3*8√ (x^7) = 24x³√ x

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√(45x^5y^3) • √(35xy^4)  ....let's simplify this one separately and then combine what we've got

 √(45x^5y^3) = √(9*5*x^5*y^3)= 3x²y√(5xy)

√(35xy^4) = y²√(35x)

So multiplying both of these, we have

3x²y³√(175x²y) = 3x³y³√(25*7*y) = 5*3x³y³√(7y) = 15x³y³√(7y)

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√50x^6/√2x^4   ........we can write this as √(50x^6/(2x^4))  ....and simplifying, we have

√(25x^2)   = 5x  .........pretty easy, once you simplify, huh??

I'll do a few for you:

I assume the first one is √(36x²) = √36*√x² = √6²*√x² = 6x

4√(32m⁷n⁹) = 4√32√m⁷√n⁹ = 4√(4²*2)*√(m⁶*m)*√(n⁸*n) = 4*4√2*m³√m*n⁴√n = 16m³n⁴√(2*m*n)

B. This is a tricky one!  5√(-5)*5*√(-2) = 5*i*√5*5*i*√2  where i is the "imaginary" number √(-1)

Since i² = -1, we have  5√(-5)*5*√(-2) = 25*i²*√5*√2 = -25√10

THANK YOU GUYS!!!!!!!!!