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When 0.325 moles of iron metal react copper(II) chloride solution to produce copper metal and iron(III) chloride. How many grams of copper will be produced?   2Fe +  3CuCl2--> 3Cu + 2FeCl3

 

 

How many grams of iron(III) chloride will form when 5.5 moles of iron react with chlorine gas in this synthesis reaction?   2Fe  + 3Cl2 --> 2FeCl3

 Nov 4, 2020
 #1
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From the equation   2 moles of Fe will result in 3 moles copper

   so .325 moles Fe will result in  .4875 moles Cu

 

Cu weights 63.546  gm per mole

 

.4875 moles  * 63.546  gm / mole = ..........  gm of Cu

 Nov 4, 2020
 #2
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30.978

Guest Nov 4, 2020
 #3
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You are an idiot if all you did was post an answer,,,,sheesh! DF

Guest Nov 5, 2020

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