Find the area of the region enclosed by the graph of $x^2 + y^2 = 2x - 6y + 6 + 14x - 16y + 80$.
Graph of a Circle: (x - h)^2 + (y - k)^2 = r^2
Circle with center (h, k), radius r.
Move variable terms to one side:
x2−16x+y2+22y=86
Complete the square:
(x−8)2−64+(y+11)2−121=86
(x−8)2+(y+11)2=86+121+64=271=r2
The area of the circle is πr2=271π
+400 
