Find the vertices of a square which is centered at ( -17,23), has side lenghth 4, and whose diagonals are parallel to the coordinates axes.
The diagonal length = 4√2.....and half of this length is 2√2
So the four vertices are
(-17 - 2√2 , 23)
(-17 + 2√2, 23)
(-17, 23 + 2√2)
(-17, 23 - 2√2)
See the graph here : https://www.desmos.com/calculator/vbqihksx9w
thank you!
+614 
