For part A, I'm not sure what the answer is. I tried to do the others but I'm not sure if it is correct. Please check and help with A. Please show work especially if I'm wrong because I need to know this. Thanks.

Guest Nov 13, 2019

#1**+1 **

A. As you 'read' from L to R is the graph going 'uphill' from -1 to 0 ? NO, it is not....it is DECREASING (going 'downhill')

ElectricPavlov Nov 13, 2019

#4**0 **

D it does have a 'local' minumum at x= -8 but **THE** minimum is at x=6 so I am not sure how to answer that one,,,depends on what you have learned

The others appear correct!

ElectricPavlov
Nov 13, 2019

#2**+1 **

Think about it this way:

For A you have a negative slope, and the problem is intuitively asking for a positive one.

Since they contradict, It is false.

tommarvoloriddle Nov 13, 2019

#6**+1 **

Technically.....f(x) does NOT have a minimum at x = -8 [ if I remember my Calculus correctly ]

A local minimum cannot occur at an endpoint of a function......only an absolute max or min can occur at an endpoint

So..... at x = -8 we cannot have an absolute min since we have an absolute min at x = 6 and no local minimum at any point on the graph

This might help : http://tutorial.math.lamar.edu/Classes/CalcI/MinMaxValues.aspx

CPhill Nov 13, 2019

#7**0 **

Thanx for the clarification, Chris! I wonder what her teacher wants for an answer......

ElectricPavlov
Nov 13, 2019

#8**0 **

Mmmm....I don't know....I suspect that the answrer might be "True".....they are probably not as nit-picky as Calculus is....LOL!!!

CPhill
Nov 13, 2019

#9**+1 **

Thank you for explaining more. I talked with some classmates and no one knows what the teacher wants! She isn't very strict so as long as I explain in detail why I chose what I chose, she should be happy with the answer. If not, I may only get a couple of points deducted but not a lot.

Guest Nov 13, 2019

#10**0 **

Yah, I looked around the 'net and there seems to be a lot of controversy re: this.....boils down to what your teacher's expectations are and what they have taught in class..... I guess.

ElectricPavlov
Nov 13, 2019